在下面的代码中，每次按下keycode 144时，我想在按键向下和向上之间的时间差大于1000毫秒时执行一些功能。但是我注意到，当keydown超过大约100毫秒时，它会继续重复调用keydown，而不是等待keyup监听器并最终计算与上次keydown时间的差异，这是错误的。如何以这样一种方式编程，即监听器应该只调用一次key down，直到触发kep up事件
@覆盖公共布尔调度KeyEvent（KeyEvent事件）{
long diff=0;
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
down = System.currentTimeMillis();
Log.e("current_down",String.valueOf((down)));
break;
case MotionEvent.ACTION_UP:
Log.e("current_down2",String.valueOf((down)));
//this is the time in milliseconds
diff = (System.currentTimeMillis()- down);
break;
}
int keyCode = event.getKeyCode();
Log.e("javan",String.valueOf((keyCode)));
if (event.getAction() == KeyEvent.ACTION_UP && keyCode == 144) {
if(diff >1000){
//do something
}
}
long diff = 0; // these two values should be declared at the start of the
long down = 0; // method
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
if(down == 0) {
down = System.currentTimeMillis(); // save current time if nothing is saved
Log.e("current_down",String.valueOf((down)));
}
break;
case MotionEvent.ACTION_UP:
Log.e("current_down2",String.valueOf((down)));
//this is the time in milliseconds
diff = (System.currentTimeMillis()- down);
down = 0; // if you need the value of down afterwards,
// you can create another variable and save it there,
// this should be reset to 0 after action up for your case
}
现在，当然还有其他方法，但这种方法我想不通。
