提问者:小点点

处理PGraphics椭圆不增长


我只是想用blendMode(DIFFERENCE)使圆圈增长和反转;但是半径是不变的…

int radius = 15;
int radius2 = 15;

size(500, 500);

PGraphics pg = createGraphics(500, 500);
pg.beginDraw();
pg.background(255);
pg.blendMode(DIFFERENCE);
pg.fill(255);
pg.noStroke();
pg.ellipse(width/2, height/2, radius, radius);
pg.ellipse(width/2.25, height/2.25, radius2, radius2);
pg.ellipse(width/2.25, height/1.8, radius2, radius2);
pg.ellipse(width/1.8, height/2.25, radius2, radius2);
pg.ellipse(width/1.8, height/1.8, radius2, radius2);
radius++;
pg.endDraw();


background(255);
image(pg, 0, 0);

共1个答案

匿名用户

出发地:https://github.com/processing/processing/wiki/Troubleshooting

如果你的代码有方法(它不仅仅是在静态模式下)或者需要随着时间的推移运行,它必须有一个draw()方法,否则什么都不会发生。例如,如果没有draw(),这段代码将在settings()方法之后停止。

就是这样。您需要将代码包装在draw()函数中。

这里有一个漂亮的“按钮”

int radius = 15;
int radius2 = 15;
PGraphics pg ;

void setup() {
  size(500, 500); 
  pg = createGraphics(500, 500);
}

void draw() {
  pg.beginDraw();
  pg.background(255);
  pg.blendMode(DIFFERENCE);
  pg.fill(255);
  pg.noStroke();
  pg.ellipse(width/2, height/2, radius, radius);
  pg.ellipse(width/2.25, height/2.25, radius2, radius2);
  pg.ellipse(width/2.25, height/1.8, radius2, radius2);
  pg.ellipse(width/1.8, height/2.25, radius2, radius2);
  pg.ellipse(width/1.8, height/1.8, radius2, radius2);
  radius++;
  pg.endDraw();


  background(255);
  image(pg, 0, 0);
}