Albert，我认为你担心的是你的代码不起作用。下面的代码对我来说非常有效。我认为你缺少URIUtil. codeQuery将字符串转换为URI。

我正在使用gson库，下载并将其添加到您的路径中。

要获得gson解析的类，您需要转到jsonschema2pojo。只需http://maps.googleapis.com/maps/api/geocode/json?address=Sayaji酒店附近balewadi体育场浦那

相信我，工作很容易。不要沮丧。

try {
        URL url = new URL(
                "http://maps.googleapis.com/maps/api/geocode/json?address="
                        + URIUtil.encodeQuery("Sayaji Hotel, Near balewadi stadium, pune") + "&sensor=true");
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setRequestMethod("GET");
        conn.setRequestProperty("Accept", "application/json");

        if (conn.getResponseCode() != 200) {
            throw new RuntimeException("Failed : HTTP error code : " + conn.getResponseCode());
        }
        BufferedReader br = new BufferedReader(new InputStreamReader((conn.getInputStream())));

        String output = "", full = "";
        while ((output = br.readLine()) != null) {
            System.out.println(output);
            full += output;
        }

        PincodeVerify gson = new Gson().fromJson(full, PincodeVerify.class); 
        response = new IsPincodeSupportedResponse(new PincodeVerifyConcrete(
                gson.getResults().get(0).getFormatted_address(), 
                gson.getResults().get(0).getGeometry().getLocation().getLat(),
                gson.getResults().get(0).getGeometry().getLocation().getLng())) ;
        try {
            String address = response.getAddress();
            Double latitude = response.getLatitude(), longitude = response.getLongitude();
            if (address == null || address.length() <= 0) {
                log.error("Address is null");
            }
        } catch (NullPointerException e) {
            log.error("Address, latitude on longitude is null");
        }
        conn.disconnect();
    } catch (MalformedURLException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

Geocode超文本传输协议有效，我刚刚启动它，结果如下

{
   "results" : [
      {
         "address_components" : [
            {
               "long_name" : "Pune",
               "short_name" : "Pune",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "Pune",
               "short_name" : "Pune",
               "types" : [ "administrative_area_level_2", "political" ]
            },
            {
               "long_name" : "Maharashtra",
               "short_name" : "MH",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "India",
               "short_name" : "IN",
               "types" : [ "country", "political" ]
            }
         ],
         "formatted_address" : "Pune, Maharashtra, India",
         "geometry" : {
            "bounds" : {
               "northeast" : {
                  "lat" : 18.63469650,
                  "lng" : 73.98948670
               },
               "southwest" : {
                  "lat" : 18.41367390,
                  "lng" : 73.73989109999999
               }
            },
            "location" : {
               "lat" : 18.52043030,
               "lng" : 73.85674370
            },
            "location_type" : "APPROXIMATE",
            "viewport" : {
               "northeast" : {
                  "lat" : 18.63469650,
                  "lng" : 73.98948670
               },
               "southwest" : {
                  "lat" : 18.41367390,
                  "lng" : 73.73989109999999
               }
            }
         },
         "types" : [ "locality", "political" ]
      }
   ],
   "status" : "OK"
}

编辑

关于“答案不包含足够的细节”

从所有的研究中，你都期望谷歌地图对地方、地区、城市的每一个组合都有参考。但事实仍然是，谷歌地图在自己的上下文中包含地理和反向地理。你不能指望它有一个像Sayaji Hotel、balewadi体育场附近、浦那这样的组合。网络谷歌地图会为你定位它，因为它使用了更广泛的搜索丰富的谷歌后端。谷歌api从他们自己的api收到的唯一反向地理地址。对我来说，这似乎是一个合理的工作方式，考虑到我们的印度地址系统有多复杂，第二个十字路口可能离第一个十字路口有几英里远：）

希望这对你有帮助：

public static GeoPoint getGeoPointFromAddress(String locationAddress) {
        GeoPoint locationPoint = null;
        String locationAddres = locationAddress.replaceAll(" ", "%20");
        String str = "http://maps.googleapis.com/maps/api/geocode/json?address="
                + locationAddres + "&sensor=true";

        String ss = readWebService(str);
        JSONObject json;
        try {

            String lat, lon;
            json = new JSONObject(ss);
            JSONObject geoMetryObject = new JSONObject();
            JSONObject locations = new JSONObject();
            JSONArray jarr = json.getJSONArray("results");
            int i;
            for (i = 0; i < jarr.length(); i++) {
                json = jarr.getJSONObject(i);
                geoMetryObject = json.getJSONObject("geometry");
                locations = geoMetryObject.getJSONObject("location");
                lat = locations.getString("lat");
                lon = locations.getString("lng");

                locationPoint = Utils.getGeoPoint(Double.parseDouble(lat),
                        Double.parseDouble(lon));
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
        return locationPoint;
    }

我使用，按顺序：
-谷歌地理编码APIv3（在少数情况下，这里描述了一个问题）
-地理编码器（在某些情况下，这里描述了一个问题）。

如果我没有收到谷歌地理编码的结果API我使用地理编码器。