所以我一直在尝试让用户输入的字符串每n个字符有一个换行符。我发现的基本上是我写的，我对Java很陌生（Python有一个函数。填充，但我不能在Java中解决这个问题），似乎不能让我的字符串不分开单词。我将程序设置为每10个字符“\n”，但它会在中间打断一些单词…我希望它接受这个单词，并将其移动到下一行，如果它不符合10个字符的限制。
import java.util.Scanner;
public class Wrap {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter your text: ");
String newString = scan.nextLine();
newString = newString.replaceAll(".{10}", "$0\n");
System.out.println(newString);
/**第二种方法，仍然切断了单词…
StringBuilder builtString = new StringBuilder();
int i = 0;
while ((i= builtString.indexOf(newString, i + 10)) != -1) {
builtString.replace(i, i+1, "\n");
}
System.out.println(builtString);
*/
System.out.println(newString);
}
}
单词被分开了：（
输出：
This is a
test and i
t doesnt s
eem to be
working pr
operly.
Python我得到了我想要的输出，但是Java似乎没有像Python那样“简单”的textwrap功能，或者至少我还没有弄清楚
public static void main(String[] args) {
String text = "This is a test and it doesnt seem to be working properly.";
String[] works = text.split(" "); // get list of works
StringBuilder line = new StringBuilder();
StringBuilder result = new StringBuilder();
for (String work : works) {
if (line.length() + work.length() > 10) { //add line to result if it full
result.append(line).append("\n");
line = new StringBuilder(); //reset line is empty
}
line.append(work).append(" ");
}
result.append(line);
System.out.println(result.toString());
}
