尝试实现以下代码:

template <typename R, typename V>
concept SizedRangeOf = 
    std::ranges::sized_range<R> &&
    std::same_as<std::ranges::range_value_t<R>, V>;

template<typename T>
const SizedRangeOf<T> auto getView(std::vector<T>& vec) {
    // helper class
    class vector_view {
        std::vector<T>& vec;
    public:
        vector_view(std::vector<T>& vec): vec(vec) {}
        auto begin() const { return vec.begin(); }
        auto end() const { return vec.end(); }
        std::size_t size() const { return vec.size(); }
    };
    return vector_view { vec };
}

int main() {
    std::vector<int> v = {1, 3, 5};
    auto r = getView(v);
    v.push_back(7);
    for(auto val: r) {
        std::cout << val << ' '; // 1 3 5 7
    }
}

在Clang 11.0中编译并运行良好，但在GCC 10.2中失败，出现以下错误:

the value of 'std::is_same_v<int, T>' is not usable in a constant expression

是GCC的bug吗？还是代码有问题？