我正在尝试格式化从csv文件创建的数组。在将其解析为正确的格式后，我需要一种方法来删除我在csv文件中遇到的重复项。
这是我拥有的数组的一个示例
[{
"pccs": ["1ADA"],
"markets": [{
"origin": "LAX",
"destination": "DFW"
}, {
"origin": "LAX",
"destination": "IAH"
}, {
"origin": "LAX",
"destination": "IAH"
}, {
"origin": "LAX",
"destination": "IAH"
}]
}, {
"pccs": ["1ABA"],
"markets": [{
"origin": "LAX",
"destination": "JFK"
}]
}]
我试图将其格式化为仅为列表中的每个元素显示一个唯一集，以获得如下响应：
[{
"pccs": ["1ADA"],
"markets": [{
"origin": "LAX",
"destination": "DFW"
}, {
"origin": "LAX",
"destination": "IAH"
}]
}, {
"pccs": ["1ABA"],
"markets": [{
"origin": "LAX",
"destination": "JFK"
}]
}]
我倾向于使用filter（）函数，但不确定如何用对象列表实现它。我需要创建一个嵌套循环来访问每个元素吗？
可以使用every（）创建一个助手函数来比较两个对象。然后在数组每个元素的市场上使用filter（），并移除所需元素。
注意：我使用了forEach，code将修改原始数组，因为我认为您需要修改原始数组。如果不是这样，请询问我，我将添加其他解决方案。
const arr = [{ "pccs": ["1ADA"], "markets": [{ "origin": "LAX", "destination": "DFW" }, { "origin": "LAX", "destination": "IAH" }, { "origin": "LAX", "destination": "IAH" }, { "origin": "LAX", "destination": "IAH" }] }, { "pccs": ["1ABA"], "markets": [{ "origin": "LAX", "destination": "JFK" }] }]
const compObjs = (obj1, obj2) => Object.keys(obj1).every(k => obj1[k] === obj2[k])
arr.forEach(x => {
x.markets = x.markets.filter(a => x.markets.find(b => compObjs(b,a)) === a)
})
console.log(arr)