我的任务是使用HashMaps和set制作同义词词典。我的主要方法中有以下代码:
public static void main(String[] args) {
addSynonym("casa", "imobil");
addSynonym("casa", "cladire");
addSynonym("casa", "locuinta");
addSynonym("casa", "camin");
addSynonym("casa", "domiciuliu");
addSynonym("jucarie", "joc");
addSynonym("jucarie", "marioneta");
addSynonym("jucarie", "papusa");
addSynonym("jucarie", "pantin");
addSynonym("om", "barbat");
addSynonym("om", "persoana");
afisarearray(getSynonyms("camin"));
}
插入同义词和键的一种方法:
static Map<String, ArrayList<String>> synonymTable = new HashMap<String, ArrayList<String>>();
public static void addSynonym(String word, String synonym) {
ArrayList<String> checklist = synonymTable.get(word);
if (checklist == null) {
ArrayList<String> temporarylist = new ArrayList<String>();
temporarylist.add(synonym);
synonymTable.put(word, temporarylist);
} else {
synonymTable.get(word).add(synonym);
}
}
显示ArrayList的一种方法:
public static void afisarearray(ArrayList<String> list) {
if (list != null) {
for (String s : list) {
System.out.println(s + "\n");
}
} else {
System.out.println("Empty list");
}
};
我想找到一个单词的所有同义词,例如单词“camin”。我写了下面的方法来做这件事,但是它不起作用,它返回一组空的键:
public static ArrayList<String> getSynonyms(String word) {
if (word == "") {
System.out.println("No word to serach for ");
return null;
} else {
Set<String> keySet = new HashSet<String>();
for (Map.Entry<String, ArrayList<String>> entry : synonymTable.entrySet()) {
if (entry.getValue().equals(word)) {
keySet.add(entry.getKey());
}
}
if (keySet.isEmpty()) {
System.out.println("No keys found");
return null;
} else {
ArrayList<String> newlist = new ArrayList<String>();
for (String s : keySet) {
newlist.addAll(synonymTable.get(s));
}
return newlist;
}
}
}
问题是在这里面,如果:
if (entry.getValue().equals(word))
是数组列表和字符串之间的比较。我不知道如何纠正它。
试试这个,我还清理了一下你的代码,以提高可读性
public static List<String> getSynonyms(String word) {
if (word == null || word.trim().isEmpty()) {
System.out.println("No word to serach for ");
return null;
}
Set<String> keySet = new HashSet<String>();
for (Map.Entry<String, List<String>> entry : synonymTable.entrySet()) {
if (entry.getValue().contains(word)) {
keySet.add(entry.getKey());
}
}
if (keySet.isEmpty()) {
System.out.println("No keys found");
return null;
}
//de-dupe and sort
Collection<String> terms = new TreeSet<>();
for (String s : keySet) {
terms.addAll(synonymTable.get(s));
}
return new ArrayList<>(terms);
}