我对Yii2还很陌生。我用的是高级结构
我需要在不使用模型的视图中显示自定义的sql结果，因为我想显示一个sql视图。
index.php
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'COD_RISORSA',
[
'label' =>"Nome",
'attribute' => 'NOME',
'value'=>function($data){
return $data["NOME"];
}
],
'COGNOME',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
VRisorseController.php
public function actionIndex()
{
$totalCount = Yii::$app->db->createCommand('SELECT COUNT(*) FROM v_risorse')->queryScalar();
$dataProvider = new SqlDataProvider([
'sql' => 'SELECT * FROM v_risorse',
'totalCount' => $totalCount,
'sort' =>false,
'pagination' => [
'pageSize' => 10,
],
]);
return $this->render('index', [
'dataProvider' => $dataProvider,
]);
}
我有一个错误：
不支持–yii\base\NotSupportedException消息格式“number”仅支持整数值。您必须安装PHP intl扩展才能使用此功能。1.在C:\xampp\htdocs\advanced\vendor\yiisoft\yii2\i18n\MessageFormatter中。php
我试图注释gridview中的所有列，错误似乎与$dataProvider变量有关
“COD_RISORSA”、“NOME”、“COGNOME”是select的列。
你需要安装PHP intl扩展。我有同样的错误
下面是我在控制器中的工作代码
$count = Yii::$app->db->createCommand('
SELECT COUNT(*) FROM screen_ticket_booking_history WHERE status=:status
', [':status' => 0])->queryScalar();
$sql = "SELECT A1.booking_id As Booking_id,
A1.booking_date As Booking_date,
A2.movie_name As Movie,
A3.theatre_name As Theatre,
A1.amount As Amount
FROM
screen_ticket_booking_history A1
LEFT OUTER JOIN movies A2 ON A1.movie_id=A2.id
LEFT OUTER JOIN theatres A3 ON A1.theatre_id=A3.id
LEFT OUTER JOIN users_backend A4 ON A3.users_backend_id=A4.id
WHERE A1.booking_date = '{$day}'
AND A1.movie_id='{$movies->id}'";
//~ $models = $dataProvider->getModels(); //print_r($models);die();
if( $userid != '1')
{
$sql .= " AND A3.users_backend_id = '{$userid}' ";
}
$dataProvider = new SqlDataProvider([
'sql' => $sql,
'totalCount' => $count,
]);
return $this->render('index',
[ 'model' => $model,
'dataProvider' => $dataProvider,
]);
}
下面是我的观点
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'Booking_id',
'Booking_date',
'Movie',
'Theatre',
'Amount',
//~ ['class' => 'yii\grid\ActionColumn'],
],
]); ?>
我遇到了同样的问题，很容易解决。您需要按以下方式分配数据库：
public function actionIndex()
{
$totalCount = Yii::$app->db->createCommand('SELECT COUNT(*) FROM v_risorse')->queryScalar();
$dataProvider = new SqlDataProvider([
**'db' => Yii::$app->db,**
'sql' => 'SELECT * FROM v_risorse',
'totalCount' => $totalCount,
'sort' =>false,
'pagination' => [
'pageSize' => 10,
],
]);
return $this->render('index', [
'dataProvider' => $dataProvider,
]);
}
你需要撤销评论
extension=php\umysql。动态链接库
和
扩展=php_mysqli.dll
在php中。伊尼，让我知道是否有效
