我不太喜欢JavaScript，我有以下问题。
我有一个这样的JSON文档：
{
"forecast": [
{
"day-1": {
"forecast_date": "2017-11-23",
"morning": {
"weather": {
"meteo_forecast_id": 19,
"meteo_forecast_date_time": "2017-11-23 06:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 26,
"max_temp": 31,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
},
"afternoon": {
"weather": {
"meteo_forecast_id": 20,
"meteo_forecast_date_time": "2017-11-23 12:00:00",
"meteo_forecast_description_id": 1,
"min_temp": 33,
"max_temp": 27,
"meteo_forecast_description_name": "Mostly Cloudy",
"meteo_forecast_description": "Mostly Cloudy",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Mostly_Cloudy_Icon.png"
}
}
}
},
{
"day-2": {
"forecast_date": "2017-11-24",
"morning": {
"weather": {
"meteo_forecast_id": 22,
"meteo_forecast_date_time": "2017-11-24 06:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 30,
"max_temp": 34,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
},
"afternoon": {
"weather": {
"meteo_forecast_id": 23,
"meteo_forecast_date_time": "2017-11-24 12:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 34,
"max_temp": 31,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
}
}
}
}
如您所见，有一个名为forecast的数组，其中包含一些对象{}，而对象{}又包含一个“day-X”：{…}包含一些其他字段的objet。
好的，我的问题是：我必须删除这些day-X对象，并将内容直接放在主{}对象中。
因此，从前面的数组开始，我必须获得如下内容：
{
"forecast": [
{
"forecast_date": "2017-11-23",
"morning": {
"weather": {
"meteo_forecast_id": 19,
"meteo_forecast_date_time": "2017-11-23 06:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 26,
"max_temp": 31,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
},
"afternoon": {
"weather": {
"meteo_forecast_id": 20,
"meteo_forecast_date_time": "2017-11-23 12:00:00",
"meteo_forecast_description_id": 1,
"min_temp": 33,
"max_temp": 27,
"meteo_forecast_description_name": "Mostly Cloudy",
"meteo_forecast_description": "Mostly Cloudy",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Mostly_Cloudy_Icon.png"
}
}
},
{
"forecast_date": "2017-11-24",
"morning": {
"weather": {
"meteo_forecast_id": 22,
"meteo_forecast_date_time": "2017-11-24 06:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 30,
"max_temp": 34,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
},
"afternoon": {
"weather": {
"meteo_forecast_id": 23,
"meteo_forecast_date_time": "2017-11-24 12:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 34,
"max_temp": 31,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
}
}
]
}
什么是明智的做法？从最初的forecast数组开始，如何删除day-x包装对象并将其内容保存到{…}这个数组的对象元素？我必须在纯JavaScript中完成，不能使用第三方库或框架
使用map迭代并使用对象返回第一个值。数组中每个项目的值。
obj.forecast = obj.forecast.map( s => Object.values(s)[0] )
演示
var obj = {
"forecast": [
{
"day-1": {
"forecast_date": "2017-11-23",
"morning": {
"weather": {
"meteo_forecast_id": 19,
"meteo_forecast_date_time": "2017-11-23 06:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 26,
"max_temp": 31,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
},
"afternoon": {
"weather": {
"meteo_forecast_id": 20,
"meteo_forecast_date_time": "2017-11-23 12:00:00",
"meteo_forecast_description_id": 1,
"min_temp": 33,
"max_temp": 27,
"meteo_forecast_description_name": "Mostly Cloudy",
"meteo_forecast_description": "Mostly Cloudy",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Mostly_Cloudy_Icon.png"
}
}
}
},
{
"day-2": {
"forecast_date": "2017-11-24",
"morning": {
"weather": {
"meteo_forecast_id": 22,
"meteo_forecast_date_time": "2017-11-24 06:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 30,
"max_temp": 34,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
},
"afternoon": {
"weather": {
"meteo_forecast_id": 23,
"meteo_forecast_date_time": "2017-11-24 12:00:00",
"meteo_forecast_description_id": 2,
"min_temp": 34,
"max_temp": 31,
"meteo_forecast_description_name": "Light Rain",
"meteo_forecast_description": "Light Rain",
"meteo_forecast_description_audio_link": "audio_link.html",
"icon_link": "Light_Rain.png"
}
}
}
}
]
};
obj.forecast = obj.forecast.map( s => Object.values(s)[0] );
console.log( obj );
假设您需要先读取文件：
const fs = require('fs');
fs.readFile('/path/to/file.json', (err, file) => {
const document = JSON.parse(file);
document.forecast = document.forecast.map((days) => {
return Object.keys(days).reduce((day, key) => days[key], {});
});
// console.log(document) or do what you want.
}
对象。values（）answer其他人提供的值也应该有效，而不是我的对象。keys（）在此处进行简化，但请注意对象。values（）支持较少，因为它是一种更新得多的方法。
