下面的代码读取csv文件的一列。这是正确的。我想将var记录复制到十进制数组。我正在使用csv助手。怎样做最好?
using (var reader = new StreamReader(filename))
using (var csv = new CsvReader(reader, CultureInfo.InvariantCulture))
{
var records = new List<Filevalues>();
csv.Read();
csv.ReadHeader();
while (csv.Read())
{
var record = new Filevalues
{
File_vals = csv.GetField<decimal>("File_vals"),
};
records.Add(record);
}
}
public class Filevalues
{
public decimal File_vals{ get; set; }
}
最简单的是:
using var csv = new CsvReader(new StreamReader(filename), CultureInfo.InvariantCulture));
csv.GetRecords<Filevalues>().Select(f => f.File_vals).ToArray();
(我想我应该列出()它而不是数组,然后使用列表)
如果CSV非常简单,只是一个小数列表,我可能会跳过使用CSV库:
File.ReadLines(path).Skip(1).Select(decimal.Parse).ToArray();
要么:
using (var reader = new StreamReader(filename))
using (var csv = new CsvReader(reader, CultureInfo.InvariantCulture))
{
var listOfDecimals = new List<decimal>();
csv.Read();
csv.ReadHeader();
while (csv.Read())
{
listOfDecimals.Add(csv.GetField<decimal>("File_vals"));
}
var arrayOfDecimals = listOfDecimals.ToArray();
}
今天:https://docs.microsoft.com/en-us/dotnet/api/system.linq.enumerable.toarray
或:
using (var reader = new StreamReader(filename))
using (var csv = new CsvReader(reader, CultureInfo.InvariantCulture))
{
var records = new List<Filevalues>();
csv.Read();
csv.ReadHeader();
while (csv.Read())
{
var record = new Filevalues
{
File_vals = csv.GetField<decimal>("File_vals"),
};
records.Add(record);
}
var arrayOfDecimals = records.Select(x => x.File_vals).ToArray();
}
public class Filevalues
{
public decimal File_vals{ get; set; }
}
LINQ投影:https://docs.microsoft.com/en-us/dotnet/csharp/programming-guide/concepts/linq/projection-operations