我试图从字典（dict）中打印'x'的值，在它从字符串（str）中找到与列表（list）中的任何元素匹配之后。
>>> dict = {'c3750': 'switch', 'vsrx': 'vfirewall'}
>>> list = ['c3750', 'vsrx']
>>> str = "Juniper Networks, Inc. firefly-perimeter internet router, kernel JUNOS 12.1X47-D15.4 #0: 2014-11-12 02:13:59 UTC builder@chamuth.juniper.net:/volume/build/junos/12.1/service/12.1X47-D15.4/obj-i386/junos/bsd/kernels/VSRX/kernel Build date: 2014-11-12 "
>>> if any(x in str.lower() for x in list):
... print "{}".format(dict['x'])
...
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
KeyError: 'x'
预期结果:它应返回“vfirewall”。
Try应该是您正在寻找的内容:
dct = {'c3750': 'switch', 'vsrx': 'vfirewall'}
lst = ['c3750', 'vsrx']
s = "Juniper Networks, Inc. firefly-perimeter internet router, kernel JUNOS 12.1X47-D15.4 #0: 2014-11-12 02:13:59 UTC builder@chamuth.juniper.net:/volume/build/junos/12.1/service/12.1X47-D15.4/obj-i386/junos/bsd/kernels/VSRX/kernel Build date: 2014-11-12 "
for x in lst:
if x in s.lower():
print("{}".format(dct[x]))
您应该使用循环来搜索列表中的每个元素。
你是说这样的事吗？
dd = {'c3750': 'switch', 'vsrx': 'vfirewall'}
ll = ['c3750', 'vsrx']
ss = "Juniper Networks, Inc. firefly-perimeter internet router, kernel JUNOS 12.1X47-D15.4 #0: 2014-11-12 02:13:59 UTC builder@chamuth.juniper.net:/volume/build/junos/12.1/service/12.1X47-D15.4/obj-i386/junos/bsd/kernels/VSRX/kernel Build date: 2014-11-12 "
[dd[x] for x in ll if x in ss.lower()]
Out[1]:
['vfirewall']
