我想比较ifs语句上的一些枚举，这就是我的意思，但这是行不通的。 基本上，我想看看是否受伤是相同的枚举，所以如果，例如，受伤是出血，你需要绷带等，如果你需要任何其他信息，请让我知道。
static string injuries = GetInjuriesName(GetInjuries(closestPlayer));
EPedInjuries result;
if (Enum.TryParse(injuries, out result) && result == EPedInjuries.Overdose)
{
.....
}
else if (Enum.TryParse(injuries, out result) && result == EPedInjuries.GunShotWound)
{
....
}
....
public enum EPedInjuries
{
OpenFracture,
GunShotWound,
Fever,
BrokenLeg,
BrokenArm,
BrokenRib,
Overdose,
.....
}
public static EPedInjuries GetInjuries(Ped ped)
{
Ped = ped;
int num = API.Common.Random.Next(0, 101);
if (num >= 0 && num <= 37)
{
return EPedInjuries.Overdose;
}
if (num > 37 && num <= 55)
{
return EPedInjuries.GunShotWound;
}
if (num > 55 && num <= 72)
{
return EPedInjuries.CardiacArrest;
}
....
}
public static string GetInjuriesName(EPedInjuries injuries)
{
string result = string.Empty;
switch (injuries)
{
case EPedInjuries.Overdose:
result = "~r~Overdose";
break;
case EPedInjuries.GunShotWound:
result = "~r~Gunshot Wound";
break;
case EPedInjuries.CardiacArrest:
result = "~r~Cardiac Arrest";
break;
....
}
return result;
}
您的GetInjuriesName返回的字符串不是正确的枚举值和枚举。TryParse无法分析该字符串，并返回false:
var injuries = GetInjuriesName(EPedInjuries.Overdose);
Console.WriteLine(injuries); //prints "~r~Overdose"
Console.WriteLine(Enum.TryParse(injuries, out EPedInjuries result)); // prints "False"
只需引入两个字段/变量，一个用于名称，一个用于伤害枚举值:
EPedInjuries injury = GetInjuries(closestPlayer)
string injuryName = GetInjuriesName(injury);
并使用第一个来处理逻辑:
if(injury == EPedInjuries.Overdose)
{
....
}
.....
GetJurines方法已经返回要比较的枚举类型。 正如@Johnny Mopp所指出的，您正在获取枚举，并将其转换为某个字符串，然后尝试将其转换回枚举
做就行了
EPedInjuries result = GetInjuries(closestPlayer);
if (result == EPedInjuries.Overdose)
{
.....
}
else if (result == EPedInjuries.GunShotWound)
{
....
}
