提问者:小点点

使用Swagger/OpenAPI创建可扩展模型


在我的API,我想有一个简单的模型为我的收藏和一个更详细的模型为我的个人资源。例如:

/库的GET请求应该返回

BaseLibrary:
    type: object
    properties:
        library_id:
          type: string
          description: The id of the library
        display_name:
          type: string
          description: Name of the library
        href:
          type: string
          description: The URI linking to this library.

而对特定库的请求应返回上述所有内容,包括额外的参数书籍:

因此,对库/{library_id}的GET请求应该返回:

ExtendedLibrary:
    type: object
    properties:
        library_id:
          type: string
          description: The id of the library
        display_name:
          type: string
          description: Name of the library
        href:
          type: string
          description: The URI linking to this library.
        books:
          type: array
          description: The books in this library
          items:
            $ref: "#/definitions/books"

我非常希望不必定义两次“BaseLibrary”,并且希望简单地为一个额外的“ExtendedLibrary”建模,该库包含基础库和附加图书属性的所有响应。

我尝试了很多不同的东西,最接近成功的是以下定义:

definitions:
  BaseLibrary:
    type: object
    properties:
        library_id:
          type: string
          description: The id of the library.
        display_name:
          type: string
          description: Name of the library
        href:
          type: string
          description: The URI linking to this library.

  ExtendedLibrary:
    type: object
    properties:
      $ref: "#/definitions/BaseLibrary/properties"
      books:
        type: array
        description: The available books for this library.
        items:
          $ref: "#/definitions/Book"

然而,这给了我一个“额外的JSON引用属性将被忽略:书籍”的警告,输出似乎忽略了这个额外的属性。有没有一种干净的方法来处理我的问题?或者我只需要将我的整个BaseLibrary模型复制粘贴到我的ExtendedLibrary模型中?


共1个答案

匿名用户

如评论部分所述,这可能是另一个问题的重复,但值得在这个特定示例的上下文中重复答案。解决方案是在ExtendedLibrary的定义中使用allOf属性:

definitions:
  Book:
    type: object
    properties:
      title:
        type: string
      author:
        type: string

  BaseLibrary:
    type: object
    properties:
      library_id:
        type: string
        description: The id of the library
      display_name:
        type: string
        description: Name of the library
      href:
        type: string
        description: The URI linking to this library.

  ExtendedLibrary:
    type: object
    allOf:
      - $ref: '#/definitions/BaseLibrary'
      - properties:
          books:
            type: array
            description: The books in this library
            items:
              $ref: "#/definitions/Book"

根据我的经验,SwaggerUI正确地可视化了这一点。当我将操作响应定义为ExtendedLibrarySwagger时UI显示了这个示例:

{
  "library_id": "string",
  "display_name": "string",
  "href": "string",
  "books": [
    {
      "title": "string",
      "author": "string"
    }
  ]
}

此外,Swagger Codesen做了正确的事情。至少在生成Java客户端时,它会创建一个正确扩展BaseLibraryExtendedLibrary类。