当我尝试进行JPQL JOIN查询时，会发生StackOverflow Error

提问者：小点点

当我尝试进行JPQL JOIN查询时，会发生StackOverflow Error

我有以下实体：

@Data
@Entity
@Table(name = "artist")
public class Artist {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name="artist_id")
    private int id;
    @Column(name="artist_name", length = 2000)
    private String name;
    private String country;
    @OneToMany(mappedBy = "artist", cascade = CascadeType.ALL, fetch = FetchType.EAGER)
    private List<Song> songs = new ArrayList<>();

    public Artist(String name, String country){
        this.name=name;
        this.country=country;
    }
}

@Data
@Entity
@Table(name = "songs")
public class Song {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private int songId;
    @Column(name = "text", length = 65600)
    private String text;
    private Double rating;
    private String songName;
    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "artist_id", nullable = false)
    public Artist artist;

    public Song(String text, Double rating, String songName, Artist artist) {
        this.text = text;
        this.rating = rating;
        this.songName = songName;
        this.artist = artist;
    }
}

我尝试通过艺术家名称模式获取所有歌曲：

@Query（"SELECT s from Song s WHEREs.artist.name如CONCAT（'%'，： name,'%')")
List findByArtistsName（@Param（"name"）String name）；

和所有艺术家的歌曲名称patern：

@Query("SELECT a FROM Artist a JOIN FETCH a.songs s WHERE s.songName LIKE CONCAT('%',:pattern,'%')")
List<Artist> findBySong(@Param("pattern") String songName);

为此，我分别使用该JPQL查询。但两者都给我相同的StackOverflow Error。

> 
> 
>     Caused by: java.lang.StackOverflowError: null
>       at sun.misc.FloatingDecimal$BinaryToASCIIBuffer.dtoa(FloatingDecimal.java:431)
> ~[na:1.8.0_151]
>       at sun.misc.FloatingDecimal$BinaryToASCIIBuffer.access$100(FloatingDecimal.java:259)
> ~[na:1.8.0_151]
>       at sun.misc.FloatingDecimal.getBinaryToASCIIConverter(FloatingDecimal.java:1785)
> ~[na:1.8.0_151]
>       at sun.misc.FloatingDecimal.getBinaryToASCIIConverter(FloatingDecimal.java:1738)
> ~[na:1.8.0_151]
>       at sun.misc.FloatingDecimal.toJavaFormatString(FloatingDecimal.java:70)
> ~[na:1.8.0_151]
>       at java.lang.Double.toString(Double.java:204) ~[na:1.8.0_151]
>       at java.lang.Double.toString(Double.java:644) ~[na:1.8.0_151]
>       at java.lang.String.valueOf(String.java:2994) ~[na:1.8.0_151]
>       at java.lang.StringBuilder.append(StringBuilder.java:131) ~[na:1.8.0_151]
>       at com.music.entity.Song.toString(Song.java:8) ~[classes/:na]
>       at java.lang.String.valueOf(String.java:2994) ~[na:1.8.0_151]
>       at java.lang.StringBuilder.append(StringBuilder.java:131) ~[na:1.8.0_151]
>       at java.util.AbstractCollection.toString(AbstractCollection.java:462)
> ~[na:1.8.0_151]
>       at org.hibernate.collection.internal.PersistentBag.toString(PersistentBag.java:510)
> ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
>       at java.lang.String.valueOf(String.java:2994) ~[na:1.8.0_151]
>       at java.lang.StringBuilder.append(StringBuilder.java:131) ~[na:1.8.0_151]
>       at com.music.entity.Artist.toString(Artist.java:9) ~[classes/:na]
>       at java.lang.String.valueOf(String.java:2994) ~[na:1.8.0_151]
>       at java.lang.StringBuilder.append(StringBuilder.java:131) ~[na:1.8.0_151]
>       at com.music.entity.Song.toString(Song.java:8) ~[classes/:na]
>       at java.lang.String.valueOf(String.java:2994) ~[na:1.8.0_151]
>       at java.lang.StringBuilder.append(StringBuilder.java:131) ~[na:1.8.0_151]
>       at java.util.AbstractCollection.toString(AbstractCollection.java:462)
> ~[na:1.8.0_151]

解决这个问题的正确方法是什么？

共1个答案

匿名用户

这几乎肯定是由您使用Lombok和@Data注释引起的，这是这些其他Lombok注释的快捷方式：

@ToString、@EqualsAndHashCode、所有字段上的@Getter和所有非最终字段上的@Setter，以及@必需的ArgsConstructor

@ToString注解会自动生成一个包含所有字段的toString方法。堆栈跟踪的底部指向集合上的toString方法调用，如果您跟踪堆栈，您可以发现导致堆栈溢出的循环：

AbstractCollection. toString-

您的Artist实体包含Song实体的集合，其中包含对Artist实体的引用等等。您可以看到它在调用toString方法时是如何陷入循环并最终耗尽堆栈帧/达到限制的。

删除@Data注释并仅应用子集或定义您自己的toString方法以避免循环。