提问者:小点点

如何检查最大可能回文整数


我正在做一个赋值,它要求我使用一个函数接受两个参数:字符串形式的整数,例如'1921',和整数k,例如2。该函数返回最大可能的回文整数,通过将输入数字的最多k个数字更改为任何其他数字0-9可以找到。

例如,1921年最多有两次变化,最大可能的回文数是1991年(有一次变化2-

我相信我正在使用的代码检查数字是否是回文,但没有给我最大可能的回文。

使用的代码:

def Is_palindrome(str):
    x = 0 
    for i in range (len(str)/2):
        if (str[x]) == (word[len(str)-x-1]):
            x+=1
        if x == (len(str)/2):
            return True
    return False

def longest_palindrome(str):
    lst = str.split() 
    palindromes = [] #List that contains the palindromes
    long_len = 0 #Length of the longest palindrome
    longest = "" #The actual longest palindrome
    for i in lst: 
        if Is_palindrome(i): #If the str is a palindrome
            palindromes.append(i) #Add it to the palindrome list
    for i in palindromes: #Loop through the palindrome list
        if len(i) > long_len: #If the palindrome is longer than the 
longest one
            longest = i #Set it as the longest one
            longest_len = len(i) # Set the length of the longest one to 
the length of this one
    return longest

如果您有任何建议,请告诉我!!提前感谢。


共1个答案

匿名用户

请尝试以下代码:

import sys

def maximumPalinUsingKChanges(str, k):
    palin = []

    a = 0
    b = len(str)

    while (a < b):
        palin.append(str[a])
        a = a + 1

    # Iinitialize l and r by leftmost and
    # rightmost ends
    l = 0
    r = len(str) - 1

    #  first try to make string palindrome
    while (l < r):
        # Replace left and right character by
        # maximum of both
        if (str[l] != str[r]):
            palin[l] = max(str[l], str[r])
            palin[r] = max(str[l], str[r])
            k = k - 1
        l = l + 1
        r = r - 1    

    # If k is negative then we can't make
    # string palindrome
    if (k < 0):
        print("Not possible")
        return "Not possible"

    l = 0
    r = len(str) - 1

    while (l <= r):
        # At mid character, if K>0 then change
        # it to 9
        if (l == r):
            if (k > 0):
                palin[l] = '9'

        # If character at lth (same as rth) is
        # less than 9
        if (palin[l] < '9'):
            #If none of them is changed in the
            #  previous loop then subtract 2 from K
            # and convert both to 9 
            if (k >= 2 and palin[l] == str[l] and palin[r] == str[r]):
                k -= 2
                palin[l] = '9'
                palin[r] = '9'

            #  If one of them is changed in the previous
            #  loop then subtract 1 from K (1 more is
            #  subtracted already) and make them 9  
            elif (k >= 1 and (palin[l] != str[l] or palin[r] != str[r])):
                k = k - 1
                palin[l] = '9'
                palin[r] = '9'

        l = l + 1
        r = r - 1

    print(''.join(palin))
    return ''.join(palin)

确保k是整数