我正在尝试打印一个矩形数组并在运行时出现错误。
我从我的主类发送一个数字,只是一个普通的int,例如5到我的油漆类中的getdataforshow(我发送的数字)
函数。这会在if语句中进行一些检查,以便我们知道在哪里显示矩形。到目前为止,这在我的程序中运行良好。
现在它将其保存在矩形类中,然后在运行时显示所有矩形?
另外值得一提的是,我从这个网站上了解到,一个用户在这里发布了活动方法:https://tips4java.wordpress.com/2009/05/08/custom-painting-approaches/
我的绘画课是:
class mainPanel extends JPanel
{
int processes, storedProcesses;
//for inital values of rectangles
int xCoor = 0;
int yCoor = 0;
int width = 10;
int height = 50;
static int x = 100;
int [] y = {100,150,200,250,300,350,400,450,500,550};
private ArrayList<ColoredRectangle> coloredRectangles = new ArrayList<ColoredRectangle>();
class ColoredRectangle
{
private Rectangle rectangle;
public ColoredRectangle()
{
System.out.println("REC");
}
public Rectangle getRectangle()
{
return rectangle;
}
}
public void addRectangle(ColoredRectangle rectangle)
{
coloredRectangles.add( rectangle );
repaint();
}
public mainPanel(int processFROMmain)
{
//just some jpanel looks here
}
public Dimension getPreferredSize() {
return new Dimension (1000, 1000);
}
public void getDataForDisplay (int proc)
{
//the method checks the value from "proc" to see where to display a rectangle on screen. proc comes from user i.e 5
int loop = 0;
while (loop < storedProcesses)
{
int breakloop = 0;
if (proc == loop)
{
xCoor = x;
yCoor = y[loop];
x = x + 10;
breakloop = 1;
Rectangle r = new Rectangle(xCoor, yCoor, width, height);
ColoredRectangle cr = new ColoredRectangle();
addRectangle( cr );
}
if (breakloop == 1)
{
break;
}
loop++;
}
}
public void paintComponent(Graphics g) {
super.paintComponent(g);
for (mainPanel.ColoredRectangle cr : coloredRectangles)
{
g.setColor(Color.RED );
Rectangle r = cr.getRectangle();
g.drawRect(r.x, r.y, r.width, r.height);
}
}
}
我得到的错误是:
您实际上从未将Rectgle
对象存储在您的ColoredRectange
对象中。您正在初始化一个变量,私有Rectange rectange;
但仅此而已。您应该编辑您的代码。
private Rectangle rectangle;
public ColoredRectangle(Rectangle rectangle) {
this.rectangle = rectangle;
}
并在getDataForDisplay
方法中;
Rectangle r = new Rectangle(xCoor, yCoor, width, height);
ColoredRectangle cr = new ColoredRectangle(r);
您忘记将Rectange
与ColoredRectange
连接,因此当您尝试访问矩形的一个属性时,NPE。
的(快速
Rectangle r = new Rectangle(xCoor, yCoor, width, height);
ColoredRectangle cr = new ColoredRectangle();
cr.rectangle = r; //<-- adding this line
addRectangle( cr );