提问者:小点点

File.CreateTempFile方法在Java不起作用并且获取不兼容类型错误


到目前为止,我的代码工作良好,我正在临时目录中创建文件并处理它。

但是现在我正在尝试提供我实际想要创建xml文件的特定目录。 因此,在方法CreateTMPXMLFile中,我将逻辑从return files.createTempFile(prefix,XML_SUFFIX,“/tmp/in”);更改为逻辑return file.CreateTempFile(prefix,XML_SUFFIX,“/tmp/in”);,然后我得到错误,因为Java:不兼容类型:Java.lang.String不能转换为Java.io.file

如果我试图更改这里的逻辑,那么它会影响我使用CreateTMPXMLFile方法的另一个方法。

我真不明白如何解决这个问题。 下面是我的代码:

 @Slf4j
public class InputConsumer implements Runnable {

    public static final String XML_SUFFIX = ".xml";

    private void processleifZipFile() {
        final AtomicBoolean isInsideLeiRecord = new AtomicBoolean();
        isInsideLeiRecord.set(false);
        final StringBuilder currentLeiRecordXml = new StringBuilder();

        try (FileSystem zipFs = FileSystems.newFileSystem(jobRunner.getInputZipPath(), null)) {
            Path tmpXMLPath = xmlFileFromLeiZipFile(zipFs);

            try (Stream<String> lines = Files.lines(tmpXMLPath)) {
                AtomicInteger processedLinesCounter = new AtomicInteger();
                AtomicInteger currentLineNumber = new AtomicInteger();
                lines.sequential().forEach(handleLineAndIncrementLineNumber(isInsideLeiRecord, currentLeiRecordXml, processedLinesCounter, currentLineNumber));
                log.info("{} lines of XML file inside LEIF input ZIP file {} processed.", processedLinesCounter.get(), jobRunner.getInputZipPath());
            }catch (IOException e) {
                throw new IllegalStateException("Problem reading input file at " + jobRunner.getInputZipPath() + ".", e);
            } finally {
                Files.delete(tmpXMLPath);
            }
        } catch (IOException e) {
            throw new IllegalStateException("Problem reading input file at " + jobRunner.getInputZipPath() + ".", e);
        }
    }

    private Path xmlFileFromLeiZipFile(FileSystem zipFs) {       //extracts the xml file from zip file
        log.info("Input file {} exists: {}", jobRunner.getInputZipPath(), Files.exists(jobRunner.getInputZipPath()));
        Path tmpXmlPath = createTmpXmlFile("leif__" + System.currentTimeMillis());
        for (Path rootDir : zipFs.getRootDirectories()) {
            try (Stream<Path> files = treeAt(rootDir)) {
                log.info("Trying to extract LEIF XML file from ZIP file into {}.", tmpXmlPath);
                final Path xmlFileInsideZip = files
                        .filter(isNotADir())
                        .filter(Files::isRegularFile)
                        .findFirst()
                        .orElseThrow(() -> new IllegalStateException("No file found in LEI ZIP file."));
                log.info("Path to LEIF XML file inside ZIP file: {}.", xmlFileInsideZip);
                return copyReplacing(xmlFileInsideZip, tmpXmlPath);
            }
        }
        throw new IllegalStateException("No file found in LEI ZIP file " + jobRunner.getInputZipPath() + ".");
    }
    

    private static Path createTmpXmlFile(final String prefix) {
        try {
            log.info("Creating temporary file {}{}", prefix, XML_SUFFIX);
            return File.createTempFile(prefix, XML_SUFFIX, new File("/tmp/in"));
        } catch (IOException e) {
            throw new IllegalStateException("Could not create tmp file at " + prefix + XML_SUFFIX + ". ", e);
        }
    }
    
    @NotNull
    private static Path copyReplacing(Path from, Path to) {
        requireNonNull(from, "Trying to copy from a path, which is null to path " + to + ".");   //trying to copy file where no xml file exist in root directory
        requireNonNull(to, "Trying to copy from path " + from + " to a path, which is null.");
        try {
            return Files.copy(from, to, REPLACE_EXISTING);
        } catch (IOException e) {
            throw new IllegalStateException("Cannot copy from " + from + " to " + to + ". ", e);
        }
    }
    
}

共2个答案

匿名用户

File.CreateTempFile需要File对象作为第三个参数。 只需将“/tmp/in”包装到文件=>中即可; 返回File.createTempFile(前缀,XML_SUFFIX,new File(“/tmp/in”));,您就可以开始工作了。

所以你可以做:

File.createTempFile("prefix", "suffix", new File("/tmp/in"));

或使用NIO(推荐)

Files.createTempFile(Paths.get("/tmp/in"), "prefix", "suffix");

匿名用户

  1. 按照Slaw的建议,使用文件#CreateTempFile(路径,字符串,字符串,FileAttribute.。。) 指定创建临时文件的目录。
  2. 对Java 7或8使用路径#get(String,String.。。),或对Java 11或更高版本使用路径#of(String),将字符串转换为路径
private static Path createTmpXmlFile(final String prefix) {
    try {
        // Java 11 or later
        // return Files.createTempFile(Path.of("/tmp/in"), prefix, XML_SUFFIX);
        // Java 8
        return Files.createTempFile(Paths.get("/tmp/in"), prefix, XML_SUFFIX);
    } catch (IOException e) {
        throw new IllegalStateException("Could not create tmp file at " + prefix + XML_SUFFIX + ". ", e);
    }
}