我的意思是:我如何测量我的CPU在函数执行上花费的时间和运行我的函数所花费的挂钟时间?(我对Linux/Windows以及x86和x86_64)感兴趣。看看我想做什么(我在这里使用C++,但我更喜欢C解决方案):
int startcputime, endcputime, wcts, wcte;
startcputime = cputime();
function(args);
endcputime = cputime();
std::cout << "it took " << endcputime - startcputime << " s of CPU to execute this\n";
wcts = wallclocktime();
function(args);
wcte = wallclocktime();
std::cout << "it took " << wcte - wcts << " s of real time to execute this\n";
另一个重要的问题:这种类型的时间测量架构是独立的还是不独立的?
下面是一个在Windows和Linux以及C和C++上都能工作的复制粘贴解决方案。
正如评论中所提到的,有一个boost库可以做到这一点。但如果您不能使用boost,那么这应该可以:
// Windows
#ifdef _WIN32
#include <Windows.h>
double get_wall_time(){
LARGE_INTEGER time,freq;
if (!QueryPerformanceFrequency(&freq)){
// Handle error
return 0;
}
if (!QueryPerformanceCounter(&time)){
// Handle error
return 0;
}
return (double)time.QuadPart / freq.QuadPart;
}
double get_cpu_time(){
FILETIME a,b,c,d;
if (GetProcessTimes(GetCurrentProcess(),&a,&b,&c,&d) != 0){
// Returns total user time.
// Can be tweaked to include kernel times as well.
return
(double)(d.dwLowDateTime |
((unsigned long long)d.dwHighDateTime << 32)) * 0.0000001;
}else{
// Handle error
return 0;
}
}
// Posix/Linux
#else
#include <time.h>
#include <sys/time.h>
double get_wall_time(){
struct timeval time;
if (gettimeofday(&time,NULL)){
// Handle error
return 0;
}
return (double)time.tv_sec + (double)time.tv_usec * .000001;
}
double get_cpu_time(){
return (double)clock() / CLOCKS_PER_SEC;
}
#endif
有许多方法来实现这些时钟。但是下面是上面的代码片段所使用的:
对于Windows:
对于Linux:
下面是一个小的演示:
#include <math.h>
#include <iostream>
using namespace std;
int main(){
// Start Timers
double wall0 = get_wall_time();
double cpu0 = get_cpu_time();
// Perform some computation.
double sum = 0;
#pragma omp parallel for reduction(+ : sum)
for (long long i = 1; i < 10000000000; i++){
sum += log((double)i);
}
// Stop timers
double wall1 = get_wall_time();
double cpu1 = get_cpu_time();
cout << "Wall Time = " << wall1 - wall0 << endl;
cout << "CPU Time = " << cpu1 - cpu0 << endl;
// Prevent Code Elimination
cout << endl;
cout << "Sum = " << sum << endl;
}
输出(12个线程):
Wall Time = 15.7586
CPU Time = 178.719
Sum = 2.20259e+011
C++11。写起来容易多了!
将
#include <cstdio>
#include <ctime>
#include <chrono>
....
std::clock_t startcputime = std::clock();
do_some_fancy_stuff();
double cpu_duration = (std::clock() - startcputime) / (double)CLOCKS_PER_SEC;
std::cout << "Finished in " << cpu_duration << " seconds [CPU Clock] " << std::endl;
auto wcts = std::chrono::system_clock::now();
do_some_fancy_stuff();
std::chrono::duration<double> wctduration = (std::chrono::system_clock::now() - wcts);
std::cout << "Finished in " << wctduration.count() << " seconds [Wall Clock]" << std::endl;
好吧,简单便携!不需要ifdef_win32或linux!
如果需要更高精度,甚至可以使用
下面给出一个@lip's建议使用
#include <boost/timer/timer.hpp>
// this is wallclock AND cpu time
boost::timer::cpu_timer timer;
... run some computation ...
boost::timer::cpu_times elapsed = timer.elapsed();
std::cout << " CPU TIME: " << (elapsed.user + elapsed.system) / 1e9 << " seconds"
<< " WALLCLOCK TIME: " << elapsed.wall / 1e9 << " seconds"
<< std::endl;