例如，我有一个银行账户，限额是500欧元。首先我加400欧元，然后再加150欧元。例如，如何更改代码以添加上次添加的100欧元，然后打印；“您的限额已达到（原150欧元）的限额（剩余50欧元），无法添加。”
我现在的代码是这样的；
private double limit;
private String name;
double deposit = 0;
double balance = 0;
int numberOfDeposits = 0;
double afhaling = 0;
public Bankaccount(String name, double limit) // constructor
{
this.name = name;
this.limit = limit;
}
public boolean addDeposit(double deposit){
if(deposit < 0){
balance = balance;
return false;
}
if(deposit > 0){
balance = balance + deposit;
numberOfDeposits ++;
return true;
}
if(balance > limit){
balance = balance;
return false;
}
return false;
}
就像我在评论中写的那样。在返回之前，您需要检查是否达到限制。这里有一个更好的函数：
public boolean addDeposit(double deposit){
if(deposit <= 0){ // include the case for deposit == 0
balance = balance; // is redundant
return false;
}else{
balance = balance + deposit;
if(balance > limit){
balance = balance;
System.out.print("Can not deposit because limit is reached.");
return false;
}else {
numberOfDeposits++;
return true;
}
}
}
我对你的代码做了一些修改。让我知道这是否适合你。
public class Bankaccount {
private double limit;
private String name;
double deposit = 0;
double balance = 0;
int numberOfDeposits = 0;
double afhaling = 0;
public Bankaccount(String name, double limit) // constructor
{
this.name = name;
this.limit = limit;
}
public boolean addDeposit(double deposit) {
if (deposit <= 0) {
return false;
}
var sum = balance + deposit;
if (!(balance >= limit)) {
if (balance != limit && sum > limit) {
var amount = limit - balance;
balance += amount;
System.out.println("remaining amount " + (deposit - amount));
} else if (balance != limit && sum < limit) {
balance = sum;
}
System.out.println("your new balance is " + balance);
numberOfDeposits++;
return true;
} else {
return false;
}
}
}
