Android:混合多个AudioTrack实例?
问题内容:
我需要同时运行两个AudioTrack实例。它们必须单独运行,因为我以不同的可变采样率播放它们。我发现,如果我在同一线程中运行它们,它们将“轮流”运行。我在各自的线程中运行它们,但是音频断断续续。
关于使两个实例更好玩的任何想法?如果没有,那么即使我想以不同的采样率播放两个短缓冲区,也有一些技巧将它们混合在一起。
问题答案:
我有4个音轨同时播放,它们似乎播放得很好。在HTC Desire 1.1ghz
OC上进行测试。我有时会在穿线时遇到小故障。有时,如果所有四个都在播放,则在我尝试加入该线程时不会停止。需要做更多的测试。这是我的课程,用于播放在给定路径下记录的WAV文件
package com.ron.audio.functions;
import java.io.BufferedInputStream;
import java.io.DataInputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.InputStream;
import android.media.AudioFormat;
import android.media.AudioManager;
import android.media.AudioTrack;
public class AudioPlayManager implements Runnable {
private File fileName;
private volatile boolean playing;
public AudioPlayManager() {
super();
setPlaying(false);
}
public void run(){
// Get the length of the audio stored in the file (16 bit so 2 bytes per short)
// and create a short array to store the recorded audio.
int musicLength = (int)(fileName.length()/2);
short[] music = new short[musicLength];
try {
// Create a DataInputStream to read the audio data back from the saved file.
InputStream is = new FileInputStream(fileName);
BufferedInputStream bis = new BufferedInputStream(is);
DataInputStream dis = new DataInputStream(bis);
// Read the file into the music array.
int i = 0;
while (dis.available() > 0) {
music[i] = dis.readShort();
i++;
}
// Close the input streams.
dis.close();
// Create a new AudioTrack object using the same parameters as the AudioRecord
// object used to create the file.
AudioTrack audioTrack = new AudioTrack(AudioManager.STREAM_MUSIC,
11025,
AudioFormat.CHANNEL_CONFIGURATION_MONO,
AudioFormat.ENCODING_PCM_16BIT,
musicLength,
AudioTrack.MODE_STREAM);
// Start playback
audioTrack.play();
// Write the music buffer to the AudioTrack object
while(playing){
audioTrack.write(music, 0, musicLength);
}
}
catch(Exception e){
e.printStackTrace();
}
}
public void setFileName(File fileName) {
this.fileName = fileName;
}
public File getFileName() {
return fileName;
}
public void setPlaying(boolean playing) {
this.playing = playing;
}
public boolean isPlaying() {
return playing;
}
}