charAt()或子字符串?哪个更快?
问题内容:
我想遍历字符串中的每个字符并将字符串中的每个字符作为字符串传递给另一个函数。
String s = "abcdefg";
for(int i = 0; i < s.length(); i++){
newFunction(s.substring(i, i+1));}
要么
String s = "abcdefg";
for(int i = 0; i < s.length(); i++){
newFunction(Character.toString(s.charAt(i)));}
最终结果必须是字符串。那么有什么想法会更快或更有效吗?
问题答案:
像往常一样:没关系,但是如果您坚持花时间进行微优化,或者如果您真的想针对非常特殊的用例进行优化,请尝试以下操作:
import org.junit.Assert;
import org.junit.Test;
public class StringCharTest {
// Times:
// 1. Initialization of "s" outside the loop
// 2. Init of "s" inside the loop
// 3. newFunction() actually checks the string length,
// so the function will not be optimized away by the hotstop compiler
@Test
// Fastest: 237ms / 562ms / 2434ms
public void testCacheStrings() throws Exception {
// Cache all possible Char strings
String[] char2string = new String[Character.MAX_VALUE];
for (char i = Character.MIN_VALUE; i < Character.MAX_VALUE; i++) {
char2string[i] = Character.toString(i);
}
for (int x = 0; x < 10000000; x++) {
char[] s = "abcdefg".toCharArray();
for (int i = 0; i < s.length; i++) {
newFunction(char2string[s[i]]);
}
}
}
@Test
// Fast: 1687ms / 1725ms / 3382ms
public void testCharToString() throws Exception {
for (int x = 0; x < 10000000; x++) {
String s = "abcdefg";
for (int i = 0; i < s.length(); i++) {
// Fast: Creates new String objects, but does not copy an array
newFunction(Character.toString(s.charAt(i)));
}
}
}
@Test
// Very fast: 1331 ms/ 1414ms / 3190ms
public void testSubstring() throws Exception {
for (int x = 0; x < 10000000; x++) {
String s = "abcdefg";
for (int i = 0; i < s.length(); i++) {
// The fastest! Reuses the internal char array
newFunction(s.substring(i, i + 1));
}
}
}
@Test
// Slowest: 2525ms / 2961ms / 4703ms
public void testNewString() throws Exception {
char[] value = new char[1];
for (int x = 0; x < 10000000; x++) {
char[] s = "abcdefg".toCharArray();
for (int i = 0; i < s.length; i++) {
value[0] = s[i];
// Slow! Copies the array
newFunction(new String(value));
}
}
}
private void newFunction(String string) {
// Do something with the one-character string
Assert.assertEquals(1, string.length());
}
}